3.4.31 \(\int \frac {x^2}{(a+b x^3)^2} \, dx\) [331]

Optimal. Leaf size=16 \[ -\frac {1}{3 b \left (a+b x^3\right )} \]

[Out]

-1/3/b/(b*x^3+a)

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Rubi [A]
time = 0.00, antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {267} \begin {gather*} -\frac {1}{3 b \left (a+b x^3\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^2/(a + b*x^3)^2,x]

[Out]

-1/3*1/(b*(a + b*x^3))

Rule 267

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a + b*x^n)^(p + 1)/(b*n*(p + 1)), x] /; FreeQ
[{a, b, m, n, p}, x] && EqQ[m, n - 1] && NeQ[p, -1]

Rubi steps

\begin {align*} \int \frac {x^2}{\left (a+b x^3\right )^2} \, dx &=-\frac {1}{3 b \left (a+b x^3\right )}\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 16, normalized size = 1.00 \begin {gather*} -\frac {1}{3 b \left (a+b x^3\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^2/(a + b*x^3)^2,x]

[Out]

-1/3*1/(b*(a + b*x^3))

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Maple [A]
time = 0.12, size = 15, normalized size = 0.94

method	result	size
gosper	\(-\frac {1}{3 b \left (b \,x^{3}+a \right )}\)	\(15\)
derivativedivides	\(-\frac {1}{3 b \left (b \,x^{3}+a \right )}\)	\(15\)
default	\(-\frac {1}{3 b \left (b \,x^{3}+a \right )}\)	\(15\)
norman	\(-\frac {1}{3 b \left (b \,x^{3}+a \right )}\)	\(15\)
risch	\(-\frac {1}{3 b \left (b \,x^{3}+a \right )}\)	\(15\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(b*x^3+a)^2,x,method=_RETURNVERBOSE)

[Out]

-1/3/b/(b*x^3+a)

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Maxima [A]
time = 0.29, size = 14, normalized size = 0.88 \begin {gather*} -\frac {1}{3 \, {\left (b x^{3} + a\right )} b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^3+a)^2,x, algorithm="maxima")

[Out]

-1/3/((b*x^3 + a)*b)

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Fricas [A]
time = 0.34, size = 15, normalized size = 0.94 \begin {gather*} -\frac {1}{3 \, {\left (b^{2} x^{3} + a b\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^3+a)^2,x, algorithm="fricas")

[Out]

-1/3/(b^2*x^3 + a*b)

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Sympy [A]
time = 0.08, size = 15, normalized size = 0.94 \begin {gather*} - \frac {1}{3 a b + 3 b^{2} x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2/(b*x**3+a)**2,x)

[Out]

-1/(3*a*b + 3*b**2*x**3)

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Giac [A]
time = 1.15, size = 14, normalized size = 0.88 \begin {gather*} -\frac {1}{3 \, {\left (b x^{3} + a\right )} b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^3+a)^2,x, algorithm="giac")

[Out]

-1/3/((b*x^3 + a)*b)

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Mupad [B]
time = 0.97, size = 14, normalized size = 0.88 \begin {gather*} -\frac {1}{3\,b\,\left (b\,x^3+a\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(a + b*x^3)^2,x)

[Out]

-1/(3*b*(a + b*x^3))

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